(7x^2-8)+(3x^2+1)=

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Solution for (7x^2-8)+(3x^2+1)= equation:


Simplifying
(7x2 + -8) + (3x2 + 1) = 0

Reorder the terms:
(-8 + 7x2) + (3x2 + 1) = 0

Remove parenthesis around (-8 + 7x2)
-8 + 7x2 + (3x2 + 1) = 0

Reorder the terms:
-8 + 7x2 + (1 + 3x2) = 0

Remove parenthesis around (1 + 3x2)
-8 + 7x2 + 1 + 3x2 = 0

Reorder the terms:
-8 + 1 + 7x2 + 3x2 = 0

Combine like terms: -8 + 1 = -7
-7 + 7x2 + 3x2 = 0

Combine like terms: 7x2 + 3x2 = 10x2
-7 + 10x2 = 0

Solving
-7 + 10x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 10x2 = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 10x2 = 0 + 7
10x2 = 0 + 7

Combine like terms: 0 + 7 = 7
10x2 = 7

Divide each side by '10'.
x2 = 0.7

Simplifying
x2 = 0.7

Take the square root of each side:
x = {-0.836660027, 0.836660027}

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